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Pochodna funkcji e^(ax)

$f\left(a, x\right) =$	${\mathrm{e}}^{ax}$
$\dfrac{\mathrm{d}\left(f\left(a, x\right)\right)}{\mathrm{d}x} =$	$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left({\mathrm{e}}^{ax}\right)}}$ $=\class{steps-node}{\cssId{steps-node-2}{{\mathrm{e}}^{ax}}}{\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(ax\right)}}$ $=\class{steps-node}{\cssId{steps-node-4}{a}}{\cdot}{\mathrm{e}}^{ax}$

$f\left(a, x\right) =$

${\mathrm{e}}^{ax}$

$\dfrac{\mathrm{d}\left(f\left(a, x\right)\right)}{\mathrm{d}x} =$

$\class{steps-node}{\cssId{steps-node-1}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left({\mathrm{e}}^{ax}\right)}}$

$=\class{steps-node}{\cssId{steps-node-2}{{\mathrm{e}}^{ax}}}{\cdot}\class{steps-node}{\cssId{steps-node-3}{\tfrac{\mathrm{d}}{\mathrm{d}x}\kern-.25em\left(ax\right)}}$

$=\class{steps-node}{\cssId{steps-node-4}{a}}{\cdot}{\mathrm{e}}^{ax}$